A hemispherical bowl made of brass has inner diameter 10.5cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm2. (Assume π = 22/7)

Given

Inner diameter 10.5cm

Find out

The cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm2.

Solution

We know that

Formula for Surface area of hemispherical bowl = 2πr²

= 2×(22/7)×(5.25)2 = 173.25cm²

Cost of tin-plating 100 cm² area = Rs 16

So, Cost of tin-plating 1 cm² area = Rs 16 /100

Cost of tin-plating 173.25 cm² area = Rs. (16×173.25)/100 = Rs 27.72

Answer

Therefore, the cost of tin-plating the inner side of the hemispherical bowl at the rate of Rs 16 per 100 cm² is Rs 27.72.

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