Question

A man starts his job with a certain monthly salary and earns a fixed increment every year. If his salary was $₹1500$ after $4$ year of service and $₹1800$ after $10$ years of service, what was his starting salary and what is the annual increment?

Answer 1

Let $₹x$ be the starting salary of a man and $₹y$ be the fixed annual increment.

Then,

Salary after $4$ years of service $=₹(x+4y)$

Salary after $10$ years of service $=₹(x+10y)$

As per the question, given that,

$(x+4y)=₹1500$…………eq.$1$

$(x+10y)=₹1800$………..eq.$2$

On subtracting equation ($1$) from equation ($2$), we get,

$6y=300$

$y=\frac{300}{6}=50$

Substituting $y=50$ in equation ($1$), we get,

$x+4\times 50=1500$

$x+200=1500$

$x=1500-200$

$x=1300$

Therefore, the starting salary of a man was $₹1300$ and the annual increment is $₹50$.