A Particle Moves In A Potential Region Given By U=8X2−4X+400J. Its State Of Equilibrium Will Be− (A)0.25M (B) 8M (C) 10 M(D) 12M

The correct answer is (A)0.25M

Given:

\( U = 8x^{2} – 4x + 400J \)

Differentiate with dx; we will get F

F = 16x – 4

At equilibrium F=0

0 = 16x – 4

x = 1/4

= 0.25m

Therefore, the state of equilibrium will be at 0.25m

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