A rectangular field is to be fenced on three sides leaving a side of $20 m$ uncovered. If the area of the field is $680 m^{2}$ , how many metres of fencing will be required.

Open in App

Solution

The length of one side is 20 m and the area is $680 m^{2}$ .
⇒ Length of another side $= \frac{680}{20}$ $= 34 m$
The length of fencing required for the three sides $= 34 + 34 + 20$
$= 88 m$
Hence the required fence is $88 m$

Suggest Corrections

Similar questions

Q. A rectangular field is to be fenced on three sides leaving a side of

20 m

uncovered. If the area of the field is

680 m^{2}

, how many metres of fencing will be required.

A rectangular field is to be fenced on three sides leaving a side of $20$ feet uncovered if the area of the field is $680$ square feet. how many feet of fencing is required.

Q. A rectangular field

242

metres long has got an area of

4840

m^{2}

. What will be the cost of fencing required to cover all the four sides, if one metre of fencing costs

5

paise?

Q. The fencing required to fence two sides of a square field of area 4.84

m^{2}

Q. A field is in the shape of a regular hexagon(all sides equal). The wire required to fence one side of the hexagon is 7 m then find the total length of the wire in metres that is required to fence the field twice.

Join BYJU'S Learning Program

A rectangular field is to be fenced on three sides leaving a side of 20m uncovered. If the area of the field is 680m2, how many metres of fencing will be required.

The length of one side is 20 m and the area is 680m2.⇒ Length of another side =68020=34mThe length of fencing required for the three sides =34+34+20 =88mHence the required fence is 88m

A rectangular field is to be fenced on three sides leaving a side of $20 m$ uncovered. If the area of the field is $680 m^{2}$ , how many metres of fencing will be required.

The length of one side is 20 m and the area is $680 m^{2}$ .
⇒ Length of another side $= \frac{680}{20}$ $= 34 m$
The length of fencing required for the three sides $= 34 + 34 + 20$
$= 88 m$
Hence the required fence is $88 m$