Question

Eleven bags of wheat flour, each marked $5$ kg, actually contained the following weights of flour (in kg) $4.975.055.085.035.005.065.084.985.045.075.00$ Find the probability that any of these bags chosen at random contains more than$5$ kg of flour.

Answer 1

Find the required probability

As per the given parameters total number of bags present is $11$ & we have to find out the probability that any of these bags chosen at random contains more than $5$ kg of flour.

Number of bags containing more than $5$ kg of flour = $7$
Hence, the probability that any of the bags chosen at random contains more than $5$ kg of flour = (Number of bags containing more than 5 kg of flour) / (Total number of bags present)
= $\frac{7}{11}$.