Question

Factorise: $2a+6b-3{(a+3b)}^2$

Answer 1

Factorization

The given equation is,

$2a+6b-3{(a+3b)}^2=2(a+3b)-3{(a+3b)}^2$

$=(a+3b)\{2-3(a+3b\left)\right\}$

$=(a+3b)(2-3a-9b)$

Hence, the result of factorization of the given equation is $(a+3b)(2-3a-9b)$.