Question

Factorize the following using appropriate identities: $x^2-\left(\frac{y^2}{100}\right)$.

Answer 1

Factorize the given polynomial

Given: $x^2-{\left(\frac{y}{10}\right)}^2$

Use the identity $a^2-b^2=(a-b)(a+b)$

$x^2-{\left(\frac{y}{10}\right)}^2=\left(x-\frac{y}{10}\right)\left(x+\frac{y}{10}\right)$

Hence, the factorized form of the polynomial $x^2-\left(\frac{y^2}{100}\right)$ is $\left(x-\frac{y}{10}\right)$$\left(x+\frac{y}{10}\right)$.