Question

Find the probability of getting $53$ Sundays in a non leap year.

• A. $\frac{2}{7}$
• B. $\frac{1}{7}$
• C. $\frac{1}{5}$
• D. $\frac{1}{9}$

Answer 1

The correct option is B

$\frac{1}{7}$

Explanation for correct option

Finding the probability of getting $53$ Sundays in a non leap year.
Number of days in non- leap year $=365$ days
There are $52$ weeks and $1$day in non-leap year
So there will be $52$ Sunday in $52$ weeks
Number of days in a week $=7$days
So that $1$day will be either of $7$days
Probability of getting $53$ Sundays in a non leap year$=\frac{1}{7}$

Hence, Option B is correct