Question

Find the square of $3a-4b$.

Answer 1

Find the square using algebraic identity.

We can use the identity ${(a-b)}^2=a^2-2ab+b^2$, to find the square of $3a-4b$

On applying the above identity, we get,

$$\begin{gathered} {(3a-4b)}^2 \\ ={\left(3a\right)}^2-2\left(3a\right)\left(4b\right)+{\left(4b\right)}^2 \\ =9a^2-24ab+16b^2 \end{gathered}$$
Hence, the square of $3a-4b$ is $9a^2-24ab+16b^2$.