Given
x2 – 16x+a=(x+b)2
Find out
We have to find the values of a and b
Solution
x2 – 16x+a=(x+b)2
We will expand (x+b)2 using the identity (a+b)2
We get the equation as
x2 – 16x+a=x2 +2bx+b2
On equating the coefficients on LHS and RHS
-16=2b
b=-16/2
b=-8
Again on equating coefficients
a=b2
a=(-8)2
a=64
Hence, a=64 and b=-8
Answer
In the given equation x2 – 16x+a=(x+b)2 the value of a is 64 and b is -8
