How can I determine if and when a molecule has or needs a resonance structure?

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Solution

Resonance Structure:
A particle can have resonance structures when it has a lone pair or a double bond on the atom close to a double bond.
At the point when you can draw at least two Lewis structures for a particle, varying just in the locations of the electrons, the actual structure is none except is a resonance hybrid of them all.
Lewis structure of Nitrite $({NO}_{2}^{-})$ :
The central atom must be the least electronegative atom. $(N)$
Draw a skeleton structure in which other atoms are single-bonded to the central molecule: $(O - N - O)$
Here the number of valence electrons is 18 in $(O - N - O)$
Draw a structure with electron pairs in which every atom should have an octet rule. $[: \underset{. .}{\overset{. .}{O}} - N (: :) - \overset{. .}{\underset{. .}{O}} :]$
The number of valence electrons in $[: \underset{. .}{\overset{. .}{O}} - N (: :) - \overset{. .}{\underset{. .}{O}} :]$ are 20.
The number of valence electrons present in $[: \underset{. .}{\overset{. .}{O}} - N (: :) - \overset{. .}{\underset{. .}{O}} :]$ are more when compared to $(O - N - O)$
Draw another structure, this time adding one double bond for every additional set of electrons: $(O = N - O)$ and $(O - N = O)$ (two prospects)
Right here, the two prospects let us know that we will have two resonance structures.

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