To prepare a 1 M HCl solution, which has a specific gravity of 1.18 with the HCl solution having 35% purity let us follow the following steps
Let us assume that we want to prepare 1 L of 1 mol/L HCl.
Step 1. Calculate the moles of HCl needed.
Moles of HCl=1L HCl ×1 mol HCl / 1L HCl=1 mol HCl
Step 2. Calculate the mass of HCl Needed.
Mass of HCl=1mol HCl× 36.46 g HC / l1mol HCl=36.46 g HCl
Step 3. Calculate the mass of solution required.
Mass of soln=36.46g HCl×100 g soln / 35g HCl=104.2 g soln
Step 4. Calculate the volume of solution required.
Volume of soln=104.2g soon × 1 mL soln / 1.18g soln=88 mL soln
To make 1 L of 1 mol/L HCl, we take 88 mL of the concentrated solution and add water to make a total of 1 L.