We know that,
N1V1 = N2V2
(½ x 200) = (1/10 x V2)
100 = (V2/10)
V2 = 1000ml
Therefore, the volume of water added = 1000-200 = 800ml
We know that,
N1V1 = N2V2
(½ x 200) = (1/10 x V2)
100 = (V2/10)
V2 = 1000ml
Therefore, the volume of water added = 1000-200 = 800ml
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