Question

If the end correction of an open pipe is 0.8 cm then the inner radius of that pipe will be

Answer 1

Step1: Given

End correction of an open pipe is 0.8 cm

Step2: Formula used

End correction

When a forceful blast of air is allowed to flow from the pipe, high-frequency notes known as overtones can be heard in the pipe, and end correction is the distance between the antinodes and the pipe's open end.

$\Delta l=1.2\times r[where\Delta l=endcorrection,r=innerradius]$

Step3: Given data

End correction of pipe is, $\Delta l=0.8cm$

Step4: Calculating the inner radius of the pipe

$$\begin{gathered} \Delta l=1.2\times r \\ 0.8=1.2\times r \\ r=\frac{0.8}{1.2} \\ r=\frac{8}{12} \\ r=\frac{4}{6} \\ r=\frac{2}{3}cm \end{gathered}$$

Hence, the inner radius of the pipe will be $\frac{2}{3}cm$