In a transformer, the output current and voltage are respectively $4 A$ and $20 V$ . If the ratio of the number of turns in the primary to secondary is $2 : 1$ what is the input current and voltage?

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Solution

Step 1: Given data
Let $N_{P}$ be the number of turns of the primary coil, $V_{P}$ be the voltage across the primary coil and $I_{P}$ be the current flowing through the primary coil.
Let $N_{S}$ be the number of turns of the secondary coil, $V_{S}$ be the voltage across the secondary coil and $I_{S}$ be the current flowing through the secondary coil.
We know that,
$\frac{N_{S}}{N_{P}} = \frac{I_{P}}{I_{S}} = \frac{V_{S}}{V_{P}}$
It is given that,
$\frac{N_{P}}{N_{S}} = \frac{2}{1}, V_{S} = 20 V$ and $I_{S} = 4 A$
Step 2: Calculate the input voltage and current
Upon substituting this in the given equation we get,
$V_{P} = \frac{N_{P}}{N_{S}} \times V_{S}$
$= \frac{2}{1} \times 20$
$= 40 V$
Again,
$I_{P} = \frac{N_{S}}{N_{P}} \times I_{S}$
$= \frac{1}{2} \times 4$
$= 2 A$
Hence, the input current of the transformer is $2 A$ and the input voltage of the transformer is $40 V$ .

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In a transformer, the output current and voltage are respectively 4A and 20V. If the ratio of the number of turns in the primary to secondary is 2:1 what is the input current and voltage?

In a transformer, the output current and voltage are respectively $4 A$ and $20 V$ . If the ratio of the number of turns in the primary to secondary is $2 : 1$ what is the input current and voltage?