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Question

Isotopes of Chlorine with mass number 35 and 37 exist in ratio?


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Solution

Isotope:

  • Isotopes are the atoms of the same element having different mass numbers and the same atomic number.
  • They have the same number of electrons and protons while the number of neutrons in each isotope is different.

Step 1: Considering the molecular weight of the isotopes:
The molecular weight of the isotope of Chlorine with an atomic mass of 35 can be taken as = M1
The molecular weight of the isotope of Chlorine with atomic mass 37 can be taken as =M2

Step 2: Considering the relative abundance of the isotopes:
The relative abundance of the isotope of Chlorine with atomic mass 35 be = x
The relative abundance of the isotope of Chlorine with atomic mass 37 is =100x
Step 3:Formula for calculating the average molecular mass :

Now, Let's consider the average molecular weight to beM

Thus, average molecular mass can be calculated as;
M=M1×x+M2(100x)100

Step 4: Putting the values in the above formula to calculate the relative abundance of each isotope:
Now we will put the given values in the given formula and calculate the percentage existence of both the isotopes of Chlorine.
35.5=35×x+37(100x)1003550=35x+37(100x)

On doing the simplification we have,
3550=35x+370037x37x35x=37003500
2x=150x=75
Hence, we have got value for the relative abundance of the Chlorine of atomic mass 35 is =75
We can calculate, the relative abundance of Chlorine with an atomic mass of 37 = 100x=10075=25
Step 5: calculating the ratio of the relative abundance of two isotopes:

The ratio of Chlorine with atomic mass 35 to Chlorine 37 = 75:25= 3:1


Therefore the isotope of Chlorine with atomic mass 35 and 37 exists in the ratio of 3:1


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