and crystallize in Bcc and Fcc type of crystals respectively. What will be the number of atoms of and present in the unit cell of their Respective crystal
Step 1 Number of atoms in
crystallizes in BCC crystals.
The BCC cell consists of one atom at the center and eight atoms at the corners
In the BCC lattice, 8 atoms are present at 8 corners of the BCC unit cell.
So each atom contributes to the unit cell,
The number of corner atoms in is
The number of center atoms in = 1
The total number of atoms in is
Therefore, the number of atoms of present in the unit cell of their respective crystal will be 2.
Step 2 Number of atoms in
crystallizes in FCC crystals.
The FCC cell consists of one atom at each of the six faces and eight atoms at eight corners.
In the FCC lattice, 8 atoms are present at 8 corners of the BCC unit cell.
So each atom contributes to the unit cell,
The number of corner atoms in is
In the FCC lattice, 6 atoms are present at 6 corners of the FCC unit cell.
So each atom contributes to the unit cell.
Number of atoms present at the edges in =
The total no of atoms(n) in is
Therefore, the number of atoms of present in the unit cell of their respective crystal will be 4.