Solve 23x-29y=98And 29x-23y=110
Consider
23x–29y=98.....129x–23y=110.....2
Now by adding both equations 1 and 2, we get
23x-29y+29x-23y=98+11052x–52y=20852(x–y)=208(x–y)=20852x–y=4.......3
Now by subtracting 1 from 2 , we get
29x-23y-23x-29y=110-9829x-23y-23x+29y=126x+6y=12x+y=2......4
Now by solving3and4, we get
x+y=2x-y=42x=6x=62x=3
Now by substituting the value of xin 4, we get
x+y=23+y=2y=2-3y=-1
Hence, x=3andy=-1
Solve for x and y:23x-29y=98 29x-23y=110
Solve for x and y:
23x−29y=98,29x−23y=110.