The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant K and compresses it by length L. The maximum momentum of the block after collision is?

a) Zero

b) ML2/K

c) √MKL

d) KL2/2M

Answer: c) √MKL

Solution:

The block of mass M moving on the frictionless horizontal surface

(1/2)mv2 = (1/2)kL2

v = L√(K/m)

Maximum momentum, mv = mL√(K/m)

= L√KM

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