Question

The$\mathrm{C}-\mathrm{O}-\mathrm{C}$ Bond Angle In Diethyl Ether Is:

• A. $109°$
• B. $110°.$.
• C. $120°$
• D. .$180°.$

Answer 1

The correct option is B

$110°.$.

Explanation for the correct option:

Option(B):

• Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.
• This intermixing usually results in the formation of hybrid orbitals having entirely different energies, shapes, etc.
• The structure of Diethyl ether is similar to water i.e bent in the shape
• And ethyl groups in the compound being larger as compared to hydrogens in water, are more repelled by the lone pairs of oxygen
• Thus ethyl groups go farther and the bond angle is increased

Explanation for the incorrect option:$120°$

Option a) $109°$

• The total deflection between two bonds is $110°$
• Thus option is incorrect

Option c) $120°$

• The angle in bent hybridization is lower than $120°$
• Thus option is incorrect

Option d) $180°$

• Since the shape is not linear
• Thus this option is incorrect

Hence The C−O−C Bond Angle In Diethyl Ether Is $110°$.