Question

The IUPAC name of ${\mathrm{CH}}_2=\mathrm{CHCHOH}-{\mathrm{CH}}_2\mathrm{CHO}$ is_______________.

Answer 1

Numbering of ${\mathrm{CH}}_2=\mathrm{CHCHOH}-{\mathrm{CH}}_2\mathrm{CHO}$

• Numbering of the given compound is as follows:-

$$\begin{gathered} {\mathrm{CH}}_2=\mathrm{CHCHOH}-{\mathrm{CH}}_2-\mathrm{CHO} \\ 54321 \end{gathered}$$

IUPAC of ${\mathrm{CH}}_2=\mathrm{CHCHOH}-{\mathrm{CH}}_2\mathrm{CHO}$

• Determination of Root Word

Select the continuous chain with the maximum number of carbon atoms

Here the chain is having five carbon atoms, hence root word will be “pent”.

• Determination of names and positions of Locants

There is no substituent in the given compound.

• Determination of primary Suffix

As this compound contains one double bond at the 4th position, the suffix will be “ene”.

• Determination of secondary Suffix
• Two functional groups are present in the given compound that is alcohol and aldehyde.
• The principal functional group is the aldehyde group; hence the parent chain will be suffixed with “al”.
• So, alcohol is considered a prefix and it is in the third position.

Hence, the IUPAC name of the given compound is 3-Hydroxy-pent-4-en-1-al.