Question

The odometer of the car reads $2000\mathrm{Km}$ at the start of the trip and $2400\mathrm{Km}$ at the end of the trip. If the trip took $8\mathrm{H}$, Calculate the average speed of the car in ${\mathrm{kmh}}^{-1}$ and ${\mathrm{ms}}^{-1}$.

Answer 1

Step 1: Given

Initial distance $d_i=2000\text{Km}$

Final distance $d_f=2400\text{Km}$

Time $t=8\text{h}$

Step 2: To Find

Average Speed Of The Car.

Step 3: Calculate average speed of the car

$$\begin{gathered} v_{avg}=\frac{d_f-d_i}{t} \\ =\frac{2400\text{Km}-2000\text{Km}}{8\text{h}} \\ =\frac{400\text{Km}}{8\text{h}} \\ =50\frac{\text{Km}}{\text{h}} \\ =\frac{50\times {10}^3\text{m}}{3600\text{s}} \\ =13.88\frac{\text{m}}{\text{s}} \end{gathered}$$

Hence, the average speed of the car is $50\frac{\text{Km}}{\text{h}}$ or $13.88\frac{\text{m}}{\text{s}}$.