Question

The zeros of the quadratic polynomial $x^2+99x+127$ are:

• A. Both positive
• B. Both negative
• C. One positive and one negative
• D. Both equal

Answer 1

The correct option is B

Both negative

Quadratic equations are the polynomial equations of degree 2 in one variable of type :$f\left(x\right)=a{x}^2+bx+c=0wherea,b,c,\in Randa\ne 0.$
Given polynomial is $x^2+99x+127$
$Heresumofzeros=\frac{-b}{a}=\frac{-99}{1}=-99$
$Productofzeros=\frac{c}{a}=\frac{127}{1}=127$
So both the zeros will be negative.

Hence, option b is the answer.