Question

What do we yield after oxidative phosphorylation of 1 molecule of glucose?

Answer 1

Oxidative phosphorylation:

1. It is a metabolic procedure, in which the exchange of electrons occurs for the generation of ATP (adenosine triphosphate).
2. It is a part of cellular respiration, which produces the maximum number of ATPs.
3. Oxidative phosphorylation of one glucose molecule produces 38 ATPs.

The following are the reactions that shows generations of 38 ATPs:

Glycolysis:

${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6+2\mathrm{ADP}+2\mathrm{Pi}+2\mathrm{NAD}+\to 2\mathrm{Pyruvic}\mathrm{acid}+2\mathrm{ATPs}+2\mathrm{NADH}+2{\mathrm{H}}^{+}+2{\mathrm{H}}_2\mathrm{O}$

Acetyl CoA formation:

$2\mathrm{Pyruvic}\mathrm{acid}+2\mathrm{CoA}+2{\mathrm{NAD}}^{+}\to 2\mathrm{Acetyl}\mathrm{CoA}+2{\mathrm{CO}}_2+2\mathrm{NADH}+2{\mathrm{H}}^{+}$

Krebs Cycle:

$2\mathrm{Acetyl}\mathrm{CoA}+6{\mathrm{NAD}}^{+}+2\mathrm{ADP}+2\mathrm{Pi}+2\mathrm{FAD}+2{\mathrm{H}}_2\mathrm{O}\to 4{\mathrm{CO}}_2+6\mathrm{NADH}+6{\mathrm{H}}^{+}+2\mathrm{ATPs}+2{\mathrm{FADH}}_2+2\mathrm{CoA}$

Electron transport system (oxidative phosphorylation):

$6{\mathrm{O}}_2+10\mathrm{NADH}+10{\mathrm{H}}^{+}+2{\mathrm{FADH}}_2+34\mathrm{ADP}+2\mathrm{Pi}\to 10{\mathrm{NAD}}^{+}+2\mathrm{FAD}+12{\mathrm{H}}_2\mathrm{O}+34\mathrm{ATP}$

Thus, a total of 38 ATPs are gained after oxidative phosphorylation of one molecule of glucose.