CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Open in App
Solution

The boiling point depends on the concentration of the sugar solution.

Let us assume that we have dissolved 2000 g of sugar in 1 kg of water.

The formula for boiling point elevation ΔTb is

ΔTb=i Kbm

Where,

i is Vant’s Hoff factor

Kb is the molal boiling point elevation constant

m is the molality of the solution

The molal concentration b of the solution must be calculated

Moles of sucrose=2000 sucrose × 1 sucrose/ 342.30 g sucrose = 5.843 mol sucrose

b=moles of solute / kilograms of solvent=5.483/1=5.483 mol/kg

Here

As sugar is non electrolyte i is 1

Kb is 0.515°C.mo.kg−1

m is 5.483 mol/kg

ΔTb=1×0.515×5.483=2.824°C

Tb=Tb° + ΔTb=100+2.824=102.824°C

The Boiling point of sugar is 102.824 °C


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Elevation in Boiling Point
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon