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Question

When acidified K2Cr2O7 solution is added to Sn2+ salt, then Sn2+ changes to:


A

Sn

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B

Sn+

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C

Sn3+

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D

Sn4+

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Solution

The correct option is D

Sn4+


The explanation for the correct option:

(D) Sn4+

  • The electronic configuration of Sn is [Kr]4d105s25p2.
  • According to this configuration, Sn can exist in +2 and +4 oxidation state by either losing two or four electrons.
  • As acidified K2Cr2O7 solution is an oxidising agent, therefore, it causes the oxidation of Sn2+ions to the highest oxidation state.
  • Thus, Sn2+ is oxidised to Sn4+ and Cr in +6 oxidation state is reduced to +3 oxidation state.

3Sn2++Cr2O72-+14H+→3Sn4++2Cr3++7H2OTin(II)dichromateionStannicChromium(III)cation

The explanation for the incorrect options:

(A) Sn

  • Oxidation refers to an increase in the oxidation state.
  • Thus, the oxidising agent cannot change Sn2+to Sn.

(B) Sn+

  • Oxidation refers to an increase in the oxidation state.
  • Thus, the oxidising agent cannot change Sn2+to Sn+.

(C) Sn3+

  • Oxidation refers to an increase in the oxidation state.
  • Thus, the oxidising agent cannot change Sn2+to Sn3+ as it is not the highest oxidation state.

Hence, option (D) is correct. When acidified K2Cr2O7 solution is added to Sn2+ salt, then Sn2+ changes to Sn4+.


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