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Question

When phenyl magnesium bromide is reacted with t-Butyl alcohol it gives


A

Ph-H

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B

Ph-OH

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C

Ph-O-C-CH2-CH3

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D

Ph-O-C-CH2-CH2-CH3

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Solution

The correct option is A

Ph-H


Explanation for correct option:

(a) Ph-H(C6H6)

  • PhMgBr+tBuOHC6H6+tBuOMgBr(Benzene)
  • The resulting product is benzene.
  • When a Grignard reagent, such as phenyl MgBr combines with alcohol, we obtain alkane, which corresponds to the alkyl portion of the Grignard reagent.
  • Because the C atom is more electronegative than the Mg atom, the alkyl portion serves as a nucleophile, absorbing an active H to produce the equivalent alkane.
  • Hence it is the correct option.

Explanation for incorrect options :

(a) Ph-OH

  • The resulting product is benzene
  • Ph-OH is not the product.
  • Hence this option is not correct

(b) Ph-O-C-CH2-CH3

  • The resulting product is benzene
  • Ph-O-C-CH2-CH3 is not the product.
  • Hence this option is not correct

(d) Ph-O-C-CH2-CH2-CH3

  • The resulting product is benzene
  • Ph-O-C-CH2-CH2-CH3 is not the product.
  • Hence this option is not correct

Therefore the correct option is (a) Ph-H.


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