Question

When the temperature goes up, the pressure inside a rigid container will _______.

Answer 1

Gay-Lussac’s Law:

Gay-law Lussac's is a gaseous law that states that a gas's pressure varies significantly with its own absolute temperature. In other circumstances, while the mass is completely fixed and the volume is constant, this same pressure produced by a gas is directly proportional to its temperature.

Mathematically, this law can be represented as:

$$\begin{gathered} \mathrm{P}\propto \mathrm{T} \\ \frac{\mathrm{P}}{\mathrm{T}}=\mathrm{k} \end{gathered}$$

or,

$\left(\frac{P_1}{T_1}\right)=\left(\frac{P_2}{T_2}\right)$

Here,

P is the pressure exerted by the gas.

T is the absolute temperature of the gas.

k is a constant.

P₁ is the initial pressure.

T₁ is the initial temperature.

P₂ is the final pressure.

T₂ is the final temperature.

Explanation:

1. Pressure and Temperature have a direct connection in a closed system with a constant volume. Whenever it comes to rising and decreasing, one variable accompanies the same alteration in a direct relationship.
2. For example, whenever the pressure rises, so does the temperature. Whenever the pressure drops, so does the temperature. If a result, as the pressure of a given system increases, so does the temperature of that system, and conversely.

Therefore, When the temperature goes up, the pressure inside a rigid container will go up.