Question

Which of the following arguments are correct and which are not correct? Give reasons for your Solution:

• A. If two coins are tossed simultaneously there are three possible outcomes—two heads, two tails, or one of each. Therefore, for each of these outcomes, the probability is $\frac{1}{3}$.
• B. If a die is thrown, there are two possible outcomes—an odd number or an even number. Therefore, the probability of getting an odd number is $\frac{1}{2}$

Answer 1

The correct option is B

If a die is thrown, there are two possible outcomes—an odd number or an even number. Therefore, the probability of getting an odd number is $\frac{1}{2}$

Determine the given choices.

For Option A)

There are three possible results when two coins are tossed at the same time: two heads, two tails, or one of each. As a result, the likelihood of each of these scenarios is $\frac{1}{3}$.

All potential outcomes are $(H,H);(H,T);(T,H)and(T,T)$

As a result, P (receiving two heads) $=\frac{1}{4}$

P (receiving one of each) $=\frac{2}{4}=\frac{1}{2}$

This is an incorrect statement.

For Option B)

There are two possible results when a die is thrown: an odd number or an even number. As a result, the likelihood of receiving an odd number is $\frac{1}{2}$. This statement is valid since the two possibilities are equally likely.

Hence, the correct choice is “Option B”.