A force of 1200 N acts on a 0.5 kg steel ball as a result of a collision lasting 25 ms. If the force is in a direction opposite to the initial velocity of 14 ms-1, then the final speed of the steel ball would be

1) 24 ms-1

2) 35 ms-1

3) 12 ms-1

4) 46 ms-1

Answer: 4) 46 ms-1

Solution:

For an impulsive force of 1200 N

F = Δp/Δt

F (Δt) = Δp

– 1200 (t2 – t1 ) = P2 – P1

– 1200 x 25 x 10-3 = -mv’ – mv

1200 x 25 x 10-3 = (1/2) v’ + (1/2)v

2 x 1200 x 12 x 10-3 = v’ + v

2 x 1200 x 12 x 10-3 = v’ + 14

60 = v’ + 14

v’ = 60 – 14

= 46 m/s

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