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Question

Dual of(xy)(x1)=x(xy)y is


A

(x.y)+(x.0)=x.(x+y).y

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B

(x+y)+(x.1)=x.(x+y).y

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C

(x.y)(x.1)=x.(x+y).y

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D

None of these

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Solution

The correct option is A

(x.y)+(x.0)=x.(x+y).y


Replace'' by'+' and'' by'.'.

(x+y).(x+1)=x+(x.y)+y

Dual of(x+y).(x+1)=x+(x.y)+y is written by replacing'+' to'.' and'1' to'0' and vice versa

Dual of(x+y).(x+1)=x+(x.y)+y is

(x.y)+(x.0)=x.(x+y).y

Hence, option(A) is the correct option.


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