Question

The probability that a leap year selected at random contains $53$ Sundays is

• A. $\frac{7}{366}$
• B. $\frac{28}{183}$
• C. $\frac{1}{7}$
• D. $\frac{2}{7}$

Answer 1

The correct option is D

$\frac{2}{7}$

Explanation for the correct option

We know that a leap year has $366$days.

We have $52$ weeks and $2$ days. So, a leap year has $52$Sundays.

The remaining $2$days can be,

(Sunday, Monday),(Monday, Tuesday),(Tuesday, Wednesday),(Wednesday, Thursday),(Thursday, Friday),(Friday, Saturday),(Saturday, Sunday)

We have $7$possibilities, from these possibilities we have two Sundays in it.

So, the required probability is $\frac{2}{7}$

Hence, option(D) is the correct answer i.e. $\frac{2}{7}$