Question

0.24 g of a volatile gas upon vaporization gives 45 mL vapour at NTP. What will be the vapour density of the substances? (density of $H_2=1$)
(a) 95.39 (b) 5.973
(c) 95.93 (d) 59.73

Answer 1

The correct option is D

find out molar mass of substance

$M_w$=$22400\times \frac{0.24}{45}$

VD=$\frac{M_w}{2}$=$\frac{119.46}{2}$=59.73