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Question

0.3 g of chloroplatinate of an organic diacidic base left 0.09 g of platinum on ignition. The molecular weight (in g/mol) of the organic base is :

A
120
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B
240
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C
180
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D
60
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Solution

The correct option is B 240
Let B is the original base.
2B+H2PtCl6B2H2PtCl2ΔPt

Equivalent weight of B2H2PtCl2=2B+2+195+6×35.5 =2B+410

Weight of ChloroplatinateWeight of Pt=Ew of saltEw of Pt

0.30.09=2B+410195

Equivalent weight of base =120

Molecular weight of base =Ew×Acidity =120×2=240 g/mol

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