Question

0.5264 gm silver bromide is obtained from 0.5124 gm of an organic compound. Calculate the percentage of bromine in the compound rounded to the nearest integer.

Answer 1

Mass of organic compound, W = 0.5124 gm
Mass of silver bromide, $W_1=0.5264gm$
$AgBr\equiv Br$
188 gm 80 gm
Percentage of bromine $=\frac{80}{188}\times \frac{W_1}{W}\times 100$

$=\frac{80}{188}\times \frac{0.5264}{0.5124}\times 100=43.71$%