Question

$0.984g$ of chloroplatinate salt of a diacid base on ignition gave $0.39g$ of platinum. Find the molecular mass of the base.

• A. 92
• B. 85
• C. 82
• D. None of these

Answer 1

The correct option is C 82

Mass of chloroplatinate salt=$0.984g$

Mass of $Pt=0.39g$

$\frac{0.984}{molecularmassofsalt}=\frac{0.39}{195}$

Let $E$ be the equivalent mass of the base, then

molecular mass of salt $\left(B_2{H}_{2}PtC{l}_6\right)$

=$2E+410$

$\Rightarrow \frac{0.984}{2E+410}=\frac{0.39}{195}$

$E=\frac{1}{2}[\frac{0.984\times 195}{0.39}-410]=41$

Molecular mass of base=$41\times 2=82$