Question

$1.00kg$ of ${}^{235}U$ undergoes fission process. If energy released per event is $200MeV$, then the total energy released is

• A. $5.12\times {10}^{24}MeV$
• B. $6.02\times {10}^{23}MeV$
• C. $5.12\times {10}^{26}MeV$
• D. $6.02\times {10}^{26}MeV$

Answer 1

The correct option is C $5.12\times {10}^{26}MeV$

$M=1kg$
No. of moles $=n=$$\frac{1000}{235}=4.2553$
No. of atoms of $U=$$n{N}_A=2.562\times {10}^{24}$ atoms
Energy released per atom $=200MeV$
Total energy released $=200\times 2.562\times {10}^{24}=5.12\times {10}^{26}MeV$