1.25 moles of a gas A and y moles of a gas B exert a pressure of 300 Pa in a container of volume 10m3 at 1000K. Find the value of y in terms of R (where R is the gas constant in JK−1mol−1 )
A
125R
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B
3R
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C
12−5R4R
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D
15−4R5R
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Solution
The correct option is C12−5R4R Total number of moles in the container (n) = 1.25 + y
Pressure = 300 Pa
Volume= 10 L
Temperature = 1000 K
We know that PV=nRT 300×10=(1.25+y)R×1000⇒y=12−5R4R