Question

1 L of a hydrocarbon weighs as much as one litre of ${CO}_2$ under similar conditions. The molecular formula of the hydrocarbon is :

• A. $C_3{H}_8$
• B. $C_2{H}_6$
• C. $C_2{H}_4$
• D. $C_3{H}_6$

Answer 1

Answer: (A)

$C_3{H}_8$

1 L of a hydrocarbon weigh as much as one litre of $C{O}_2$ under similar conditions.

Thus, 22.4 L of a hydrocarbon will weigh as much as 22.4 L of $C{O}_2$ under similar conditions.

Thus, the molecular weight of hydrocarbon is same as that of $C{O}_2$. It is 44 g/mol.

Hence, out of all hydrocarbon $C_3{H}_8$ has molecular formula 44.