Question

1 mole of carbon dioxide occupies 0.4 litres at 300 Kelvin and 40 atm pressure, the the compressibility factor is:

• A. 0.32
• B. 1.2
• C. 0.12
• D. 0.65

Answer 1

The correct option is D 0.65

The compressibility factor is a correction factor which describes the deviation of a real gas from ideal gas behaviour.

Compressibility factor, Z $=\frac{pV}{RT}$, $n=1$

on putting the values, we have

Compressibility factor, Z $=\frac{40\times 0.4}{0.0821\times 300}=0.65$