Question

$1$ mole of $N_2{H}_4$ loses $10$ mol of electrons to form a new compound $Y$. Assuming that all the nitrogen appear in the new compound, what is the oxidation state of nitrogen in $Y$? (no change in the oxidation state $H$).

Answer 1

$\underset{\uparrow }{N_2{H}_4}⟶\underset{\uparrow }{N_2}(---)+10e^{-}$
In $N_2{H}_4;2N=-4$ oxidation and it is loosing 10 electron so new N have oxidation of $=(-4+10)/2=+3$