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Derivation of Kp and Kc

1 mole of N 2...

Question

1 mole of $N_{2} O_{4} (g)$ at 300K is kept in a closed container under 1 atm pressure. It is heated to 600K when 20 $%$ by mass of $N_{2} O_{4} (g)$ decomposes to $N O_{2} (g)$ . The resultant pressure is

1.2 atm

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2.4 atm

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2.0 atm

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1.0 atm

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Solution

The correct option is B 2.4 atm
Correct option is b).
$\begin{matrix} N_{2} O_{4} ⇋ & 2 N O_{2} I n i t i a l m o l e s & 1 & 0 \end{matrix}$

Total moles=0.8+0.4=1.2

Applying, $P V = n R T$ , at constant volume,

$\frac{P 1}{n 1 T 1} = \frac{P}{n 2 T 2}$

$\frac{1}{1 X 300} = \frac{P_{2}}{1.2 X 600}$

$P_{2} = 2.4 a t m .$

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