1 mole of N2H4 loses 10 mole of electrons to form a new compound Y. Assuming that all the nitrogen appear in the new compound, what is the oxidation state of Nitrogen in Y? There is no change in the oxidation state of Hydrogen.

Open in App

Solution

Suggest Corrections

Similar questions

Q. A mole of

N_{2} H_{4}

loses 10 mol of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y ? ( There is no change in the oxidation number of hydrogen. )

Q. One mole of

N_{2} H_{4}

loses

10

moles of electrons to form a new compound

A

. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in

A

[There is no change in the oxidation state of hydrogen]

O n e m o l e

N_{2} H_{4}

loses

10 m o l e s

of electrons to form a new compound

Y

. Assuming that all nitrogen appear in the new compound, what is the oxidation state of nitrogen in compound

Y

[There is no change in the oxidation state of hydrogen.]

A mole of $N_{2} H_{4}$ loses 10 mol of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (There is no change in the oxidation number of hydrogen.)

One mole of $N_{2} H_{4}$ loses 10 mol of electrons to form a new compound Y. Assuming that all nitrogen appear in the new compound, what is the oxidation state of $N_{2}$ in Y ? (There is no change in the oxidation state of hydrogen)

Join BYJU'S Learning Program