Question

$10\text{g}$ carbon reacts with $100\text{g}$ $C{l}_2$ to form $CC{l}_4.$ The correct statement is:

• A. Carbon is the limiting reagent
• B. $C{l}_2$ is the limiting reagent
• C. $C{l}_2$ is the excess reagent
• D. $0.833$ moles of $CC{l}_4$ are formed

Answer 1

The correct option is B $C{l}_2$ is the limiting reagent

$C+2C{l}_2\to CC{l}_4$
Moles of $C=\frac{10}{12}=0.833$
Moles of $C{l}_2=\frac{100}{71}\approx 1.40$
$[\begin{array}{c}1moleC\Rightarrow 1moleCC{l}_4\\ 0.833moleC\Rightarrow 0.833moleCC{l}_4\end{array}$

$[\begin{array}{c}2moleC{l}_2\Rightarrow 1moleCC{l}_4\\ 1.40moleC{l}_2\Rightarrow 0.70moleCC{l}_4\end{array}$
$C{l}_2$ is limiting reagent because it forms least number of moles of product.