Question

11.2 litre of a gas at STP weighs 14 g. The gas could not be:

• A. $N_2$
• B. $CO$
• C. $B_2{H}_6$
• D. $N_{2}O$

Answer 1

The correct option is D $N_{2}O$

Molar mass of $N_2$, $CO$ and $B_2{H}_6$ is 28. Hence $\frac{28}{2}=14$g of these compounds occupies the volume of 11.2L
But molar mass of $N_{2}O$ is 44g. 22g of it occupies the volume of 11.2L.