Question

12 Packets of salt, each marked 2 kg, actually contained the following weights (in kg) of salt:
1.950, 2.020, 2.060, 1.980, 2.030, 1.970,
2.040, 1.990, 1.985, 2.025, 2.000, 1.980.
Out of these packets, one packet is chosen at random.
What is the probability that the chosen packet contains more than 2 kg of salt?

Answer 1

Total number of salt packets = 12

Number of packets which contains more than 2 kg of salt = 5

∴ P(Chosen packet contains more than 2 kg of salt) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{packets}\mathrm{which}\mathrm{contains}\mathrm{more}\mathrm{than}2\mathrm{kg}\mathrm{of}\mathrm{salt}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{salt}\mathrm{packets}}=\frac{5}{12}$

Thus, the probability that the chosen packet contains more than 2 kg of salt is $\frac{5}{12}$.