$13^{A l^{27}}$ is a stable isotope. $13^{A l^{29}}$ is expected to disintegrate by :

$α -$ emission

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$β -$ emission

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Position emission

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Proton emission

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Solution

The correct option is B
$β -$ emission

$\frac{n}{p}$ ratio is too large, which decreases by $β$ - emission.

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Similar questions

$13^{A l^{27}}$ is a stable isotope. $13^{A l^{29}}$ is expected to disintegrate by :

_{13}^{27} A l

_{13}^{29} A l

_{13}^{27} A l

_{13}^{29} A l

_{13}^{27} A l

_{13}^{29} A l

6 β

7 α

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