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Law of Radioactivity

13. Find nucl...

Question

13. Find nuclear mass density of 238U92. Given R= 1.5fermi and mass of each nucleon 1.67 x 10 27 kg.

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Q. The density of a nucleus in which mass of each nucleon is

1.67 \times 10^{- 27}

R_{0} = 1.4 \times 10^{- 15}

Q. The nuclear radius of

_{8} O^{16}

3 \times 10^{- 15} m

. If an atomic mass unit is

1.67 \times 10^{- 27} k g

, then the nuclear density is approximately

Q. Assume that the nuclear mass is of the order of

10^{- 27}

kg and the nuclear radius is of the order of

10^{- 15}

m.Then, nuclear density is of the order of :

Q. If the distance between nuclei is

2 \times 10^{- 13}

, the density of nuclear material is:

(mass of neuclei =

10^{- 27}

Q. Assuming the radius of nucleus to be equal to

R = 1.3 A^{1 / 3} \times 10^{- 15} m

A

is its mass number, evaluate the density of nuclei and the number of nucleons per unit volume of the nucleus. Take mass of one nucleon

= 1.67 \times 10^{- 27} k g

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