1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Roots of a Quadratic Equation
13 × 2+7 x+1=...
Question
13
x
2
+
7
x
+
1
=
0
Open in App
Solution
Given:
13
x
2
+
7
x
+
1
=
0
Comparing the given equation with the general form of the quadratic equation
a
x
2
+
b
x
+
c
=
0
, we get
a
=
13
,
b
=
7
and
c
=
1
.
Substituting these values in
α
=
-
b
+
b
2
-
4
a
c
2
a
and
β
=
-
b
-
b
2
-
4
a
c
2
a
, we get:
α
=
-
7
+
49
-
4
×
13
×
1
2
×
13
and
β
=
-
7
-
49
-
4
×
13
×
1
2
×
13
⇒
α
=
-
7
+
49
-
52
26
and
β
=
-
7
-
49
-
52
26
⇒
α
=
-
7
+
-
3
26
and
β
=
-
7
-
-
3
26
⇒
α
=
-
7
+
i
3
26
and
β
=
-
7
-
i
3
26
⇒
α
=
-
7
26
+
3
26
i
and
β
=
-
7
26
-
3
26
i
Hence, the roots of the equation are
-
7
26
±
3
26
i
.
Suggest Corrections
0
Similar questions
Q.
Find the limits of the following expression
(
3
−
x
)
(
x
+
5
)
(
2
−
7
x
)
(
7
x
−
1
)
(
x
+
1
)
3
,
(
1
)
when
x
=
∞
,
(
2
)
when
x
=
0
.
Q.
6x
2
– 7x – 13 = 0
Q.
Roots of quadratic equation
6
x
2
−
7
x
−
13
=
0
are
Q.
Solve for
x
:
√
7
x
2
−
6
x
−
13
√
7
=
0
Q.
If
α
,
β
are the roots of
x
2
+
7
x
+
5
=
0
, then the equation whose roots are
α
−
1
,
β
−
1
is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
MATHEMATICS
Watch in App
Explore more
Roots of a Quadratic Equation
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app