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Question

13x2+7x+1=0

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Solution

Given: 13x2 + 7x + 1 = 0
Comparing the given equation with the general form of the quadratic equation ax2 + bx + c = 0, we get a = 13, b = 7 and c = 1.

Substituting these values in α = -b + b2 - 4ac2a and β= -b - b2 - 4ac2a, we get:

α = -7 + 49 - 4×13×12×13 and β= -7 - 49 - 4×13×12×13

α = -7 + 49 - 5226 and β = -7 - 49 - 5226

α = -7 + -326 and β = -7 - -326

α = -7 + i326 and β = -7 - i326

α = -726 + 326i and β = -726 - 326i


Hence, the roots of the equation are -726 ± 326i.

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