1L of a buffer is created to be 0.100M in HOAc. the pKa=4.7 and 0.100M in NaOAc. What is the pH ?
A
6.7
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B
4.7
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C
1.7
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D
5.7
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Solution
The correct option is B 4.7 Given, pKa for HOAc is 4.7 [HOAc]=0.100M,[NaOAc]=0.100M
Using the Henderson-Hasselbalch equation for weak acid: pH=pKa+log[[salt][acid]] pH=pKa+log[[NaOAc][HOAc]] pH=4.7+log(0.100M0.100M) pH=4.7